Base | Representation |
---|---|
bin | 10001011110100111110… |
… | …011101010000001110111 |
3 | 11020211021111122112111001 |
4 | 101132213303222001313 |
5 | 124134333432242101 |
6 | 2315441033424131 |
7 | 152530440564424 |
oct | 21364763520167 |
9 | 4224244575431 |
10 | 1201111212151 |
11 | 42342aa6a244 |
12 | 17494986b047 |
13 | 89358892ba6 |
14 | 421c3d44d4b |
15 | 2139c538901 |
hex | 117a7cea077 |
1201111212151 has 2 divisors, whose sum is σ = 1201111212152. Its totient is φ = 1201111212150.
The previous prime is 1201111212107. The next prime is 1201111212181. The reversal of 1201111212151 is 1512121111021.
It is a strong prime.
It is an emirp because it is prime and its reverse (1512121111021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1201111212151 - 219 = 1201110687863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201111212181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600555606075 + 600555606076.
It is an arithmetic number, because the mean of its divisors is an integer number (600555606076).
Almost surely, 21201111212151 is an apocalyptic number.
1201111212151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201111212151 is an equidigital number, since it uses as much as digits as its factorization.
1201111212151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 19.
Adding to 1201111212151 its reverse (1512121111021), we get a palindrome (2713232323172).
The spelling of 1201111212151 in words is "one trillion, two hundred one billion, one hundred eleven million, two hundred twelve thousand, one hundred fifty-one".
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