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12011122003200 = 283522941526139
BaseRepresentation
bin1010111011001000111010…
…1010010000110100000000
31120112020210202002101221220
42232302032222100310000
53033242234213100300
641313455553115040
72346526541331555
oct256621652206400
946466722071856
1012011122003200
113910985272491
12141ba04558a80
1369184a992b78
142d74acb6aa2c
1515c68455dda0
hexaec8ea90d00

12011122003200 has 432 divisors, whose sum is σ = 42006302049600. Its totient is φ = 3017085747200.

The previous prime is 12011122003129. The next prime is 12011122003207. The reversal of 12011122003200 is 230022111021.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 12011122003200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12011122003207) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 22565731 + ... + 23091869.

It is an arithmetic number, because the mean of its divisors is an integer number (97236810300).

Almost surely, 212011122003200 is an apocalyptic number.

12011122003200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12011122003200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21003151024800).

12011122003200 is an abundant number, since it is smaller than the sum of its proper divisors (29995180046400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12011122003200 is a wasteful number, since it uses less digits than its factorization.

12011122003200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 526238 (or 526219 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12011122003200 its reverse (230022111021), we get a palindrome (12241144114221).

The spelling of 12011122003200 in words is "twelve trillion, eleven billion, one hundred twenty-two million, three thousand, two hundred".