Base | Representation |
---|---|
bin | 10110010111110101… |
… | …10101010001011101 |
3 | 1011000002001201120122 |
4 | 23023322311101131 |
5 | 144044322210442 |
6 | 5303504124325 |
7 | 603434636354 |
oct | 131372652135 |
9 | 34002051518 |
10 | 12011131997 |
11 | 5103a75277 |
12 | 23b26066a5 |
13 | 11955616c7 |
14 | 81d2b899b |
15 | 4a471ddd2 |
hex | 2cbeb545d |
12011131997 has 2 divisors, whose sum is σ = 12011131998. Its totient is φ = 12011131996.
The previous prime is 12011131981. The next prime is 12011132033. The reversal of 12011131997 is 79913111021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9418896601 + 2592235396 = 97051^2 + 50914^2 .
It is a cyclic number.
It is not a de Polignac number, because 12011131997 - 24 = 12011131981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011131597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005565998 + 6005565999.
It is an arithmetic number, because the mean of its divisors is an integer number (6005565999).
Almost surely, 212011131997 is an apocalyptic number.
It is an amenable number.
12011131997 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011131997 is an equidigital number, since it uses as much as digits as its factorization.
12011131997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3402, while the sum is 35.
The spelling of 12011131997 in words is "twelve billion, eleven million, one hundred thirty-one thousand, nine hundred ninety-seven".
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