12011201301037 has 2 divisors, whose sum is σ = 12011201301038. Its totient is φ = 12011201301036.

The previous prime is 12011201301031. The next prime is 12011201301049. The reversal of 12011201301037 is 73010310211021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6870511199556 + 5140690101481 = 2621166^2 + 2267309^2 .

It is a cyclic number.

It is not a de Polignac number, because 12011201301037 - 2¹⁹ = 12011200776749 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12011201300999 and 12011201301017.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12011201301031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005600650518 + 6005600650519.

It is an arithmetic number, because the mean of its divisors is an integer number (6005600650519).

Almost surely, 2^{12011201301037} is an apocalyptic number.

It is an amenable number.

12011201301037 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011201301037 is an equidigital number, since it uses as much as digits as its factorization.

12011201301037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 12011201301037 its reverse (73010310211021), we get a palindrome (85021511512058).

The spelling of 12011201301037 in words is "twelve trillion, eleven billion, two hundred one million, three hundred one thousand, thirty-seven".