12011210112133 has 2 divisors, whose sum is σ = 12011210112134. Its totient is φ = 12011210112132.

The previous prime is 12011210112067. The next prime is 12011210112137. The reversal of 12011210112133 is 33121101211021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11826672854049 + 184537258084 = 3438993^2 + 429578^2 .

It is an emirp because it is prime and its reverse (33121101211021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12011210112133 - 2¹⁷ = 12011209981061 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12011210112133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12011210112137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005605056066 + 6005605056067.

It is an arithmetic number, because the mean of its divisors is an integer number (6005605056067).

Almost surely, 2^{12011210112133} is an apocalyptic number.

It is an amenable number.

12011210112133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011210112133 is an equidigital number, since it uses as much as digits as its factorization.

12011210112133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 12011210112133 its reverse (33121101211021), we get a palindrome (45132311323154).

The spelling of 12011210112133 in words is "twelve trillion, eleven billion, two hundred ten million, one hundred twelve thousand, one hundred thirty-three".