Base | Representation |
---|---|
bin | 1010111011001001001111… |
… | …1010011100011000111111 |
3 | 1120112021000212220202120202 |
4 | 2232302103322130120333 |
5 | 3033242424243143012 |
6 | 41313512422034115 |
7 | 2346531661366133 |
oct | 256622372343077 |
9 | 46467025822522 |
10 | 12011210131007 |
11 | 3910a1aa9518a |
12 | 141ba29b7893b |
13 | 69186300a8b9 |
14 | 2d74ba74b3c3 |
15 | 15c68c16acc2 |
hex | aec93e9c63f |
12011210131007 has 2 divisors, whose sum is σ = 12011210131008. Its totient is φ = 12011210131006.
The previous prime is 12011210130973. The next prime is 12011210131049. The reversal of 12011210131007 is 70013101211021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12011210131007 - 210 = 12011210129983 is a prime.
It is a super-2 number, since 2×120112101310072 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12011210131007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011210131057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005605065503 + 6005605065504.
It is an arithmetic number, because the mean of its divisors is an integer number (6005605065504).
Almost surely, 212011210131007 is an apocalyptic number.
12011210131007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011210131007 is an equidigital number, since it uses as much as digits as its factorization.
12011210131007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 12011210131007 its reverse (70013101211021), we get a palindrome (82024311342028).
The spelling of 12011210131007 in words is "twelve trillion, eleven billion, two hundred ten million, one hundred thirty-one thousand, seven".
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