120112111112117 has 2 divisors, whose sum is σ = 120112111112118. Its totient is φ = 120112111112116.

The previous prime is 120112111112027. The next prime is 120112111112171. The reversal of 120112111112117 is 711211111211021.

Together with next prime (120112111112171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101188993407076 + 18923117705041 = 10059274^2 + 4350071^2 .

It is a cyclic number.

It is not a de Polignac number, because 120112111112117 - 2¹⁶ = 120112111046581 is a prime.

It is a super-2 number, since 2×120112111112117² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120112111112092 and 120112111112101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120112111112197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056055556058 + 60056055556059.

It is an arithmetic number, because the mean of its divisors is an integer number (60056055556059).

Almost surely, 2^{120112111112117} is an apocalyptic number.

It is an amenable number.

120112111112117 is a deficient number, since it is larger than the sum of its proper divisors (1).

120112111112117 is an equidigital number, since it uses as much as digits as its factorization.

120112111112117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 23.

Adding to 120112111112117 its reverse (711211111211021), we get a palindrome (831323222323138).

The spelling of 120112111112117 in words is "one hundred twenty trillion, one hundred twelve billion, one hundred eleven million, one hundred twelve thousand, one hundred seventeen".