Base | Representation |
---|---|
bin | 11011010011110111000111… |
… | …110110001110000111110001 |
3 | 120202021121100200202101201021 |
4 | 123103313013312032013301 |
5 | 111220404102001442431 |
6 | 1103242424302135441 |
7 | 34204546065464611 |
oct | 3323670766160761 |
9 | 522247320671637 |
10 | 120112113312241 |
11 | 352a9296715066 |
12 | 1157a647881581 |
13 | 52036a66c5a9b |
14 | 2193658ba6a41 |
15 | dd45d2044b11 |
hex | 6d3dc7d8e1f1 |
120112113312241 has 2 divisors, whose sum is σ = 120112113312242. Its totient is φ = 120112113312240.
The previous prime is 120112113312143. The next prime is 120112113312277. The reversal of 120112113312241 is 142213311211021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62114810877025 + 57997302435216 = 7881295^2 + 7615596^2 .
It is a cyclic number.
It is not a de Polignac number, because 120112113312241 - 225 = 120112079757809 is a prime.
It is not a weakly prime, because it can be changed into another prime (120112113319241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056056656120 + 60056056656121.
It is an arithmetic number, because the mean of its divisors is an integer number (60056056656121).
Almost surely, 2120112113312241 is an apocalyptic number.
It is an amenable number.
120112113312241 is a deficient number, since it is larger than the sum of its proper divisors (1).
120112113312241 is an equidigital number, since it uses as much as digits as its factorization.
120112113312241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 120112113312241 its reverse (142213311211021), we get a palindrome (262325424523262).
The spelling of 120112113312241 in words is "one hundred twenty trillion, one hundred twelve billion, one hundred thirteen million, three hundred twelve thousand, two hundred forty-one".
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