Base | Representation |
---|---|
bin | 1010111011001001010010… |
… | …0110000100001010110011 |
3 | 1120112021001200102201121212 |
4 | 2232302110212010022303 |
5 | 3033242440210104011 |
6 | 41313513511110335 |
7 | 2346532160523524 |
oct | 256622446041263 |
9 | 46467050381555 |
10 | 12011221566131 |
11 | 3910a264955a7 |
12 | 141ba319723ab |
13 | 6918654b2748 |
14 | 2d74bc08684b |
15 | 15c68d17908b |
hex | aec949842b3 |
12011221566131 has 2 divisors, whose sum is σ = 12011221566132. Its totient is φ = 12011221566130.
The previous prime is 12011221566101. The next prime is 12011221566269. The reversal of 12011221566131 is 13166512211021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12011221566131 is a prime.
It is a super-2 number, since 2×120112215661312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12011221566101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005610783065 + 6005610783066.
It is an arithmetic number, because the mean of its divisors is an integer number (6005610783066).
Almost surely, 212011221566131 is an apocalyptic number.
12011221566131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011221566131 is an equidigital number, since it uses as much as digits as its factorization.
12011221566131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 32.
Adding to 12011221566131 its reverse (13166512211021), we get a palindrome (25177733777152).
The spelling of 12011221566131 in words is "twelve trillion, eleven billion, two hundred twenty-one million, five hundred sixty-six thousand, one hundred thirty-one".
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