Base | Representation |
---|---|
bin | 1010111011001001010100… |
… | …0110101000011001111111 |
3 | 1120112021002021111110020101 |
4 | 2232302111012220121333 |
5 | 3033242444401300132 |
6 | 41313514414101531 |
7 | 2346532323221041 |
oct | 256622506503177 |
9 | 46467067443211 |
10 | 12011230103167 |
11 | 3910a302965a9 |
12 | 141ba347aa8a7 |
13 | 6918671b1449 |
14 | 2d74bd269a91 |
15 | 15c68dcb37e7 |
hex | aec951a867f |
12011230103167 has 2 divisors, whose sum is σ = 12011230103168. Its totient is φ = 12011230103166.
The previous prime is 12011230103123. The next prime is 12011230103177. The reversal of 12011230103167 is 76130103211021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12011230103167 - 243 = 3215137080959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011230103177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005615051583 + 6005615051584.
It is an arithmetic number, because the mean of its divisors is an integer number (6005615051584).
Almost surely, 212011230103167 is an apocalyptic number.
12011230103167 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011230103167 is an equidigital number, since it uses as much as digits as its factorization.
12011230103167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 12011230103167 its reverse (76130103211021), we get a palindrome (88141333314188).
The spelling of 12011230103167 in words is "twelve trillion, eleven billion, two hundred thirty million, one hundred three thousand, one hundred sixty-seven".
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