Base | Representation |
---|---|
bin | 1010111011001001010100… |
… | …0110111111110100101011 |
3 | 1120112021002021200022210211 |
4 | 2232302111012333310223 |
5 | 3033242444412332313 |
6 | 41313514420121551 |
7 | 2346532324100503 |
oct | 256622506776453 |
9 | 46467067608724 |
10 | 12011230199083 |
11 | 3910a30351675 |
12 | 141ba348362b7 |
13 | 691867215cbb |
14 | 2d74bd292a03 |
15 | 15c68dcd1e3d |
hex | aec951bfd2b |
12011230199083 has 2 divisors, whose sum is σ = 12011230199084. Its totient is φ = 12011230199082.
The previous prime is 12011230199081. The next prime is 12011230199093. The reversal of 12011230199083 is 38099103211021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12011230199083 - 21 = 12011230199081 is a prime.
Together with 12011230199081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12011230199081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005615099541 + 6005615099542.
It is an arithmetic number, because the mean of its divisors is an integer number (6005615099542).
Almost surely, 212011230199083 is an apocalyptic number.
12011230199083 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011230199083 is an equidigital number, since it uses as much as digits as its factorization.
12011230199083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 40.
The spelling of 12011230199083 in words is "twelve trillion, eleven billion, two hundred thirty million, one hundred ninety-nine thousand, eighty-three".
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