Base | Representation |
---|---|
bin | 1010111011001001100111… |
… | …0111111011000001001111 |
3 | 1120112021021212002101222101 |
4 | 2232302121313323001033 |
5 | 3033243130343231302 |
6 | 41313530353255531 |
7 | 2346534314401111 |
oct | 256623167730117 |
9 | 46467255071871 |
10 | 12011310133327 |
11 | 3910a7148842a |
12 | 141ba575645a7 |
13 | 69187a95247b |
14 | 2d74c9b3d3b1 |
15 | 15c695d21287 |
hex | aec99dfb04f |
12011310133327 has 2 divisors, whose sum is σ = 12011310133328. Its totient is φ = 12011310133326.
The previous prime is 12011310133309. The next prime is 12011310133409. The reversal of 12011310133327 is 72333101311021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12011310133327 is a prime.
It is a super-2 number, since 2×120113101333272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12011310133295 and 12011310133304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011310130327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005655066663 + 6005655066664.
It is an arithmetic number, because the mean of its divisors is an integer number (6005655066664).
Almost surely, 212011310133327 is an apocalyptic number.
12011310133327 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011310133327 is an equidigital number, since it uses as much as digits as its factorization.
12011310133327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 12011310133327 its reverse (72333101311021), we get a palindrome (84344411444348).
The spelling of 12011310133327 in words is "twelve trillion, eleven billion, three hundred ten million, one hundred thirty-three thousand, three hundred twenty-seven".
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