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1201131321053 is a prime number
BaseRepresentation
bin10001011110101001000…
…000010111011011011101
311020211022220111011201012
4101132221000113123131
5124134404104233203
62315443032425005
7152531103526106
oct21365100273335
94224286434635
101201131321053
11423440354374
12174954548165
138935cab3a51
14421c689b3ad
152139e1abbd8
hex117a90176dd

1201131321053 has 2 divisors, whose sum is σ = 1201131321054. Its totient is φ = 1201131321052.

The previous prime is 1201131320981. The next prime is 1201131321073. The reversal of 1201131321053 is 3501231311021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 857035280644 + 344096040409 = 925762^2 + 586597^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201131321053 - 210 = 1201131320029 is a prime.

It is a super-2 number, since 2×12011313210532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201131321073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600565660526 + 600565660527.

It is an arithmetic number, because the mean of its divisors is an integer number (600565660527).

Almost surely, 21201131321053 is an apocalyptic number.

It is an amenable number.

1201131321053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201131321053 is an equidigital number, since it uses as much as digits as its factorization.

1201131321053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 1201131321053 its reverse (3501231311021), we get a palindrome (4702362632074).

The spelling of 1201131321053 in words is "one trillion, two hundred one billion, one hundred thirty-one million, three hundred twenty-one thousand, fifty-three".