Base | Representation |
---|---|
bin | 1010111011001001101100… |
… | …0011101110000100001110 |
3 | 1120112021100020110220100010 |
4 | 2232302123003232010032 |
5 | 3033243200440100324 |
6 | 41313532343214050 |
7 | 2346534645315603 |
oct | 256623303560416 |
9 | 46467306426303 |
10 | 12011330003214 |
11 | 3910a81719a23 |
12 | 141ba62147326 |
13 | 691881abb5b9 |
14 | 2d74cc6326aa |
15 | 15c697948829 |
hex | aec9b0ee10e |
12011330003214 has 16 divisors (see below), whose sum is σ = 24022710426960. Its totient is φ = 4003768264320.
The previous prime is 12011330003201. The next prime is 12011330003297. The reversal of 12011330003214 is 41230003311021.
12011330003214 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×120113300032142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1460424 + ... + 5114244.
It is an arithmetic number, because the mean of its divisors is an integer number (1501419401685).
Almost surely, 212011330003214 is an apocalyptic number.
12011330003214 is an abundant number, since it is smaller than the sum of its proper divisors (12011380423746).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12011330003214 is a wasteful number, since it uses less digits than its factorization.
12011330003214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4201715.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 12011330003214 its reverse (41230003311021), we get a palindrome (53241333314235).
The spelling of 12011330003214 in words is "twelve trillion, eleven billion, three hundred thirty million, three thousand, two hundred fourteen".
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