Base | Representation |
---|---|
bin | 1010111011001001101101… |
… | …0100100111110101010101 |
3 | 1120112021100112211000102020 |
4 | 2232302123110213311111 |
5 | 3033243203103343013 |
6 | 41313533022203353 |
7 | 2346535031061666 |
oct | 256623324476525 |
9 | 46467315730366 |
10 | 12011334434133 |
11 | 3910a84175a41 |
12 | 141ba63723559 |
13 | 6918829b0348 |
14 | 2d74cd06736d |
15 | 15c698021623 |
hex | aec9b527d55 |
12011334434133 has 32 divisors (see below), whose sum is σ = 16249408412160. Its totient is φ = 7890811568640.
The previous prime is 12011334434129. The next prime is 12011334434153. The reversal of 12011334434133 is 33143443311021.
It is not a de Polignac number, because 12011334434133 - 22 = 12011334434129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12011334434094 and 12011334434103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12011334434153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 517785291 + ... + 517808487.
It is an arithmetic number, because the mean of its divisors is an integer number (507794012880).
Almost surely, 212011334434133 is an apocalyptic number.
It is an amenable number.
12011334434133 is a deficient number, since it is larger than the sum of its proper divisors (4238073978027).
12011334434133 is a wasteful number, since it uses less digits than its factorization.
12011334434133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27437.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 12011334434133 its reverse (33143443311021), we get a palindrome (45154777745154).
The spelling of 12011334434133 in words is "twelve trillion, eleven billion, three hundred thirty-four million, four hundred thirty-four thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •