Base | Representation |
---|---|
bin | 1010111011001001111101… |
… | …1110011000010001011011 |
3 | 1120112021112101220102222102 |
4 | 2232302133132120101123 |
5 | 3033243323422210244 |
6 | 41313543551314015 |
7 | 2346536535166343 |
oct | 256623736302133 |
9 | 46467471812872 |
10 | 12011404100699 |
11 | 391100a529513 |
12 | 141ba82b1b90b |
13 | 691894263173 |
14 | 2d74d83ddd23 |
15 | 15c69e1d354e |
hex | aec9f79845b |
12011404100699 has 2 divisors, whose sum is σ = 12011404100700. Its totient is φ = 12011404100698.
The previous prime is 12011404100687. The next prime is 12011404100753. The reversal of 12011404100699 is 99600140411021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12011404100699 is a prime.
It is not a weakly prime, because it can be changed into another prime (12011404100299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005702050349 + 6005702050350.
It is an arithmetic number, because the mean of its divisors is an integer number (6005702050350).
Almost surely, 212011404100699 is an apocalyptic number.
12011404100699 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011404100699 is an equidigital number, since it uses as much as digits as its factorization.
12011404100699 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 38.
The spelling of 12011404100699 in words is "twelve trillion, eleven billion, four hundred four million, one hundred thousand, six hundred ninety-nine".
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