Base | Representation |
---|---|
bin | 11011010011111001010000… |
… | …110100100000111001010111 |
3 | 120202021211021211220110220011 |
4 | 123103321100310200321113 |
5 | 111220423303300442242 |
6 | 1103243444313021051 |
7 | 34204660041436213 |
oct | 3323712064407127 |
9 | 522254254813804 |
10 | 120114411343447 |
11 | 352aa265910a04 |
12 | 1157ab893b4787 |
13 | 520398182ba71 |
14 | 21937d6081943 |
15 | dd46b8b77d17 |
hex | 6d3e50d20e57 |
120114411343447 has 2 divisors, whose sum is σ = 120114411343448. Its totient is φ = 120114411343446.
The previous prime is 120114411343439. The next prime is 120114411343481. The reversal of 120114411343447 is 744343114411021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120114411343447 - 23 = 120114411343439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120114411323447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60057205671723 + 60057205671724.
It is an arithmetic number, because the mean of its divisors is an integer number (60057205671724).
Almost surely, 2120114411343447 is an apocalyptic number.
120114411343447 is a deficient number, since it is larger than the sum of its proper divisors (1).
120114411343447 is an equidigital number, since it uses as much as digits as its factorization.
120114411343447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 40.
Adding to 120114411343447 its reverse (744343114411021), we get a palindrome (864457525754468).
The spelling of 120114411343447 in words is "one hundred twenty trillion, one hundred fourteen billion, four hundred eleven million, three hundred forty-three thousand, four hundred forty-seven".
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