120120011000053 has 2 divisors, whose sum is σ = 120120011000054. Its totient is φ = 120120011000052.

The previous prime is 120120010999997. The next prime is 120120011000057. The reversal of 120120011000053 is 350000110021021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88025995835089 + 32094015164964 = 9382217^2 + 5665158^2 .

It is a cyclic number.

It is not a de Polignac number, because 120120011000053 - 2¹³ = 120120010991861 is a prime.

It is a super-3 number, since 3×120120011000053³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120120011000057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060005500026 + 60060005500027.

It is an arithmetic number, because the mean of its divisors is an integer number (60060005500027).

Almost surely, 2^{120120011000053} is an apocalyptic number.

It is an amenable number.

120120011000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

120120011000053 is an equidigital number, since it uses as much as digits as its factorization.

120120011000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 120120011000053 its reverse (350000110021021), we get a palindrome (470120121021074).

The spelling of 120120011000053 in words is "one hundred twenty trillion, one hundred twenty billion, eleven million, fifty-three", and thus it is an aban number.