120120012022151 has 2 divisors, whose sum is σ = 120120012022152. Its totient is φ = 120120012022150.

The previous prime is 120120012022141. The next prime is 120120012022223. The reversal of 120120012022151 is 151220210021021.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120120012022151 is a prime.

It is a super-3 number, since 3×120120012022151³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120120012022141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060006011075 + 60060006011076.

It is an arithmetic number, because the mean of its divisors is an integer number (60060006011076).

Almost surely, 2^{120120012022151} is an apocalyptic number.

120120012022151 is a deficient number, since it is larger than the sum of its proper divisors (1).

120120012022151 is an equidigital number, since it uses as much as digits as its factorization.

120120012022151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 160, while the sum is 20.

Adding to 120120012022151 its reverse (151220210021021), we get a palindrome (271340222043172).

The spelling of 120120012022151 in words is "one hundred twenty trillion, one hundred twenty billion, twelve million, twenty-two thousand, one hundred fifty-one".