12012101333134 has 48 divisors (see below), whose sum is σ = 21543057226800. Its totient is φ = 5005025303040.

The previous prime is 12012101333131. The next prime is 12012101333159. The reversal of 12012101333134 is 43133310121021.

It is a junction number, because it is equal to n+sod(n) for n = 12012101333099 and 12012101333108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012101333131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3398142 + ... + 5964190.

It is an arithmetic number, because the mean of its divisors is an integer number (448813692225).

Almost surely, 2^{12012101333134} is an apocalyptic number.

12012101333134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

12012101333134 is a deficient number, since it is larger than the sum of its proper divisors (9530955893666).

12012101333134 is a wasteful number, since it uses less digits than its factorization.

12012101333134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2567393 (or 2567386 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12012101333134 its reverse (43133310121021), we get a palindrome (55145411454155).

The spelling of 12012101333134 in words is "twelve trillion, twelve billion, one hundred one million, three hundred thirty-three thousand, one hundred thirty-four".