Base | Representation |
---|---|
bin | 1010111011001100100100… |
… | …0100101100111000001111 |
3 | 1120112100100001011000220002 |
4 | 2232303021010230320033 |
5 | 3033301241103344211 |
6 | 41314141122114515 |
7 | 2346563041302413 |
oct | 256631104547017 |
9 | 46470301130802 |
10 | 12012102012431 |
11 | 3911338481974 |
12 | 14200387aba3b |
13 | 691975a20ba1 |
14 | 2d7562d92d43 |
15 | 15c6e05e203b |
hex | aecc912ce0f |
12012102012431 has 2 divisors, whose sum is σ = 12012102012432. Its totient is φ = 12012102012430.
The previous prime is 12012102012419. The next prime is 12012102012479. The reversal of 12012102012431 is 13421020121021.
12012102012431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12012102012431 - 210 = 12012102011407 is a prime.
It is a super-2 number, since 2×120121020124312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012102012481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006051006215 + 6006051006216.
It is an arithmetic number, because the mean of its divisors is an integer number (6006051006216).
Almost surely, 212012102012431 is an apocalyptic number.
12012102012431 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012102012431 is an equidigital number, since it uses as much as digits as its factorization.
12012102012431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 12012102012431 its reverse (13421020121021), we get a palindrome (25433122133452).
The spelling of 12012102012431 in words is "twelve trillion, twelve billion, one hundred two million, twelve thousand, four hundred thirty-one".
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