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120121022000923 is a prime number
BaseRepresentation
bin11011010011111111011010…
…110110001010111100011011
3120202022110100120000200010221
4123103333122312022330123
5111221030323113012143
61103250500302220511
734205312622212116
oct3323773266127433
9522273316020127
10120121022000923
1135302048409799
1211580313284737
1352044962852c8
142193c6200d57d
15dd49541d62ed
hex6d3fdad8af1b

120121022000923 has 2 divisors, whose sum is σ = 120121022000924. Its totient is φ = 120121022000922.

The previous prime is 120121022000909. The next prime is 120121022001089. The reversal of 120121022000923 is 329000220121021.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120121022000923 is a prime.

It is a super-2 number, since 2×1201210220009232 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120121022000123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060511000461 + 60060511000462.

It is an arithmetic number, because the mean of its divisors is an integer number (60060511000462).

Almost surely, 2120121022000923 is an apocalyptic number.

120121022000923 is a deficient number, since it is larger than the sum of its proper divisors (1).

120121022000923 is an equidigital number, since it uses as much as digits as its factorization.

120121022000923 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 120121022000923 its reverse (329000220121021), we get a palindrome (449121242121944).

The spelling of 120121022000923 in words is "one hundred twenty trillion, one hundred twenty-one billion, twenty-two million, nine hundred twenty-three", and thus it is an aban number.