Base | Representation |
---|---|
bin | 11011010011111111011010… |
… | …110110001010111100011011 |
3 | 120202022110100120000200010221 |
4 | 123103333122312022330123 |
5 | 111221030323113012143 |
6 | 1103250500302220511 |
7 | 34205312622212116 |
oct | 3323773266127433 |
9 | 522273316020127 |
10 | 120121022000923 |
11 | 35302048409799 |
12 | 11580313284737 |
13 | 52044962852c8 |
14 | 2193c6200d57d |
15 | dd49541d62ed |
hex | 6d3fdad8af1b |
120121022000923 has 2 divisors, whose sum is σ = 120121022000924. Its totient is φ = 120121022000922.
The previous prime is 120121022000909. The next prime is 120121022001089. The reversal of 120121022000923 is 329000220121021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120121022000923 is a prime.
It is a super-2 number, since 2×1201210220009232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120121022000123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060511000461 + 60060511000462.
It is an arithmetic number, because the mean of its divisors is an integer number (60060511000462).
Almost surely, 2120121022000923 is an apocalyptic number.
120121022000923 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121022000923 is an equidigital number, since it uses as much as digits as its factorization.
120121022000923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 120121022000923 its reverse (329000220121021), we get a palindrome (449121242121944).
The spelling of 120121022000923 in words is "one hundred twenty trillion, one hundred twenty-one billion, twenty-two million, nine hundred twenty-three", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •