Base | Representation |
---|---|
bin | 1010111011001100100100… |
… | …1000111001011001101100 |
3 | 1120112100100010012220121222 |
4 | 2232303021020321121230 |
5 | 3033301241344043200 |
6 | 41314141201442512 |
7 | 2346563053533134 |
oct | 256631110713154 |
9 | 46470303186558 |
10 | 12012103112300 |
11 | 3911339063255 |
12 | 1420039040438 |
13 | 6919760176b5 |
14 | 2d756319bac4 |
15 | 15c6e075cd85 |
hex | aecc923966c |
12012103112300 has 72 divisors (see below), whose sum is σ = 26384533156800. Its totient is φ = 4746278085120.
The previous prime is 12012103112281. The next prime is 12012103112311. The reversal of 12012103112300 is 321130121021.
12012103112300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×120121031123002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8597594 + ... + 9896606.
It is an arithmetic number, because the mean of its divisors is an integer number (366451849400).
Almost surely, 212012103112300 is an apocalyptic number.
12012103112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12012103112300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13192266578400).
12012103112300 is an abundant number, since it is smaller than the sum of its proper divisors (14372430044500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12012103112300 is a wasteful number, since it uses less digits than its factorization.
12012103112300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1300155 (or 1300148 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12012103112300 its reverse (321130121021), we get a palindrome (12333233233321).
The spelling of 12012103112300 in words is "twelve trillion, twelve billion, one hundred three million, one hundred twelve thousand, three hundred".
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