Base | Representation |
---|---|
bin | 1010111011001100100100… |
… | …1000111110000000010101 |
3 | 1120112100100010020212111101 |
4 | 2232303021020332000111 |
5 | 3033301241400144112 |
6 | 41314141202110101 |
7 | 2346563053642123 |
oct | 256631110760025 |
9 | 46470303225441 |
10 | 12012103131157 |
11 | 3911339076438 |
12 | 142003904b331 |
13 | 69197602315c |
14 | 2d75631a4913 |
15 | 15c6e0763757 |
hex | aecc923e015 |
12012103131157 has 2 divisors, whose sum is σ = 12012103131158. Its totient is φ = 12012103131156.
The previous prime is 12012103131139. The next prime is 12012103131247. The reversal of 12012103131157 is 75113130121021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11200795804081 + 811307327076 = 3346759^2 + 900726^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012103131157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012103135157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006051565578 + 6006051565579.
It is an arithmetic number, because the mean of its divisors is an integer number (6006051565579).
Almost surely, 212012103131157 is an apocalyptic number.
It is an amenable number.
12012103131157 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012103131157 is an equidigital number, since it uses as much as digits as its factorization.
12012103131157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 28.
Adding to 12012103131157 its reverse (75113130121021), we get a palindrome (87125233252178).
The spelling of 12012103131157 in words is "twelve trillion, twelve billion, one hundred three million, one hundred thirty-one thousand, one hundred fifty-seven".
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