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12012103131157 is a prime number
BaseRepresentation
bin1010111011001100100100…
…1000111110000000010101
31120112100100010020212111101
42232303021020332000111
53033301241400144112
641314141202110101
72346563053642123
oct256631110760025
946470303225441
1012012103131157
113911339076438
12142003904b331
1369197602315c
142d75631a4913
1515c6e0763757
hexaecc923e015

12012103131157 has 2 divisors, whose sum is σ = 12012103131158. Its totient is φ = 12012103131156.

The previous prime is 12012103131139. The next prime is 12012103131247. The reversal of 12012103131157 is 75113130121021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11200795804081 + 811307327076 = 3346759^2 + 900726^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12012103131157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12012103135157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006051565578 + 6006051565579.

It is an arithmetic number, because the mean of its divisors is an integer number (6006051565579).

Almost surely, 212012103131157 is an apocalyptic number.

It is an amenable number.

12012103131157 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012103131157 is an equidigital number, since it uses as much as digits as its factorization.

12012103131157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1260, while the sum is 28.

Adding to 12012103131157 its reverse (75113130121021), we get a palindrome (87125233252178).

The spelling of 12012103131157 in words is "twelve trillion, twelve billion, one hundred three million, one hundred thirty-one thousand, one hundred fifty-seven".