Base | Representation |
---|---|
bin | 1010111011001100100110… |
… | …0100011100010000111111 |
3 | 1120112100100121210202112222 |
4 | 2232303021210130100333 |
5 | 3033301300221123431 |
6 | 41314142020315555 |
7 | 2346563202105536 |
oct | 256631144342077 |
9 | 46470317722488 |
10 | 12012110332991 |
11 | 391134214526a |
12 | 142003b542bbb |
13 | 6919776751b2 |
14 | 2d756411b31d |
15 | 15c6e11d757b |
hex | aecc991c43f |
12012110332991 has 2 divisors, whose sum is σ = 12012110332992. Its totient is φ = 12012110332990.
The previous prime is 12012110332987. The next prime is 12012110333011. The reversal of 12012110332991 is 19923301121021.
It is a weak prime.
It is an emirp because it is prime and its reverse (19923301121021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12012110332991 - 22 = 12012110332987 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012110332091) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006055166495 + 6006055166496.
It is an arithmetic number, because the mean of its divisors is an integer number (6006055166496).
Almost surely, 212012110332991 is an apocalyptic number.
12012110332991 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012110332991 is an equidigital number, since it uses as much as digits as its factorization.
12012110332991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 35.
The spelling of 12012110332991 in words is "twelve trillion, twelve billion, one hundred ten million, three hundred thirty-two thousand, nine hundred ninety-one".
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