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120121110220022 = 2293204984829727
BaseRepresentation
bin11011010011111111100000…
…000110101100110011110110
3120202022110120201000122222222
4123103333200012230303312
5111221031013204020042
61103250513133122342
734205315043106502
oct3323774006546366
9522273521018888
10120121110220022
113530209319403a
12115803389293b2
1352044ab632762
142193c6da15302
15dd495bd102d2
hex6d3fe01accf6

120121110220022 has 8 divisors (see below), whose sum is σ = 180796619820096. Its totient is φ = 59855570279992.

The previous prime is 120121110220019. The next prime is 120121110220031. The reversal of 120121110220022 is 220022011121021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1201211102200222 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102492414278 + ... + 102492415449.

It is an arithmetic number, because the mean of its divisors is an integer number (22599577477512).

Almost surely, 2120121110220022 is an apocalyptic number.

120121110220022 is a deficient number, since it is larger than the sum of its proper divisors (60675509600074).

120121110220022 is a wasteful number, since it uses less digits than its factorization.

120121110220022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204984830022.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 120121110220022 its reverse (220022011121021), we get a palindrome (340143121341043).

Subtracting 120121110220022 from its reverse (220022011121021), we obtain a palindrome (99900900900999).

The spelling of 120121110220022 in words is "one hundred twenty trillion, one hundred twenty-one billion, one hundred ten million, two hundred twenty thousand, twenty-two".

Divisors: 1 2 293 586 204984829727 409969659454 60060555110011 120121110220022