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12012120201331 is a prime number
BaseRepresentation
bin1010111011001100101000…
…1010000101100001110011
31120112100101022101010101001
42232303022022011201303
53033301310232420311
641314143012022431
72346563352016315
oct256631212054163
946470338333331
1012012120201331
113911347775518
121420042901a17
1369197971bb53
142d75655697b5
1515c6e1ed64c1
hexaecca285873

12012120201331 has 2 divisors, whose sum is σ = 12012120201332. Its totient is φ = 12012120201330.

The previous prime is 12012120201329. The next prime is 12012120201379. The reversal of 12012120201331 is 13310202121021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12012120201331 - 21 = 12012120201329 is a prime.

It is a super-2 number, since 2×120121202013312 (a number of 27 digits) contains 22 as substring.

Together with 12012120201329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12012120201299 and 12012120201308.

It is not a weakly prime, because it can be changed into another prime (12012120202331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006060100665 + 6006060100666.

It is an arithmetic number, because the mean of its divisors is an integer number (6006060100666).

Almost surely, 212012120201331 is an apocalyptic number.

12012120201331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012120201331 is an equidigital number, since it uses as much as digits as its factorization.

12012120201331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12012120201331 its reverse (13310202121021), we get a palindrome (25322322322352).

The spelling of 12012120201331 in words is "twelve trillion, twelve billion, one hundred twenty million, two hundred one thousand, three hundred thirty-one".