Base | Representation |
---|---|
bin | 10110010111111101… |
… | …00110110000011000 |
3 | 1011000010220222101112 |
4 | 23023332212300120 |
5 | 144100100333422 |
6 | 5303541235452 |
7 | 603446226155 |
oct | 131376466030 |
9 | 34003828345 |
10 | 12012121112 |
11 | 5104590422 |
12 | 23b2a02b88 |
13 | 1195819994 |
14 | 81d49522c |
15 | 4a4866ee2 |
hex | 2cbfa6c18 |
12012121112 has 8 divisors (see below), whose sum is σ = 22522727100. Its totient is φ = 6006060552.
The previous prime is 12012121109. The next prime is 12012121201. The reversal of 12012121112 is 21112121021.
It is a tau number, because it is divible by the number of its divisors (8).
It is a super-2 number, since 2×120121211122 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750757562 + ... + 750757577.
Almost surely, 212012121112 is an apocalyptic number.
It is an amenable number.
12012121112 is a deficient number, since it is larger than the sum of its proper divisors (10510605988).
12012121112 is a wasteful number, since it uses less digits than its factorization.
12012121112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1501515145 (or 1501515141 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 12012121112 its reverse (21112121021), we get a palindrome (33124242133).
Subtracting 12012121112 from its reverse (21112121021), we obtain a palindrome (9099999909).
The spelling of 12012121112 in words is "twelve billion, twelve million, one hundred twenty-one thousand, one hundred twelve".
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