Base | Representation |
---|---|
bin | 10001011110101101110… |
… | …100101000001100110111 |
3 | 11020211112112112200212222 |
4 | 101132231310220030313 |
5 | 124140040301130403 |
6 | 2315455040432555 |
7 | 152533104432026 |
oct | 21365564501467 |
9 | 4224475480788 |
10 | 1201212130103 |
11 | 423481a28407 |
12 | 17497761875b |
13 | 8937376845b |
14 | 421d34d48bd |
15 | 213a6320338 |
hex | 117add28337 |
1201212130103 has 2 divisors, whose sum is σ = 1201212130104. Its totient is φ = 1201212130102.
The previous prime is 1201212130099. The next prime is 1201212130109. The reversal of 1201212130103 is 3010312121021.
It is a weak prime.
It is an emirp because it is prime and its reverse (3010312121021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1201212130103 - 22 = 1201212130099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201212130109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600606065051 + 600606065052.
It is an arithmetic number, because the mean of its divisors is an integer number (600606065052).
Almost surely, 21201212130103 is an apocalyptic number.
1201212130103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201212130103 is an equidigital number, since it uses as much as digits as its factorization.
1201212130103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1201212130103 its reverse (3010312121021), we get a palindrome (4211524251124).
The spelling of 1201212130103 in words is "one trillion, two hundred one billion, two hundred twelve million, one hundred thirty thousand, one hundred three".
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