Base | Representation |
---|---|
bin | 10001011110101101110… |
… | …101110010011011011110 |
3 | 11020211112120010010221200 |
4 | 101132231311302123132 |
5 | 124140040340343032 |
6 | 2315455051140330 |
7 | 152533110136320 |
oct | 21365565623336 |
9 | 4224476103850 |
10 | 1201212434142 |
11 | 423482115886 |
12 | 1749777446a6 |
13 | 89373843966 |
14 | 421d3573610 |
15 | 213a638047c |
hex | 117add726de |
1201212434142 has 24 divisors (see below), whose sum is σ = 2974430789616. Its totient is φ = 343203552576.
The previous prime is 1201212434111. The next prime is 1201212434143. The reversal of 1201212434142 is 2414342121021.
1201212434142 is a `hidden beast` number, since 1 + 2 + 0 + 1 + 2 + 1 + 243 + 414 + 2 = 666.
It is a super-2 number, since 2×12012124341422 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201212434143) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4766715883 + ... + 4766716134.
It is an arithmetic number, because the mean of its divisors is an integer number (123934616234).
Almost surely, 21201212434142 is an apocalyptic number.
1201212434142 is an abundant number, since it is smaller than the sum of its proper divisors (1773218355474).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201212434142 is a wasteful number, since it uses less digits than its factorization.
1201212434142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9533432032 (or 9533432029 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 1201212434142 its reverse (2414342121021), we get a palindrome (3615554555163).
The spelling of 1201212434142 in words is "one trillion, two hundred one billion, two hundred twelve million, four hundred thirty-four thousand, one hundred forty-two".
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