Base | Representation |
---|---|
bin | 11011010011111111101011… |
… | …011010101001110111001001 |
3 | 120202022111001221010111110111 |
4 | 123103333223122221313021 |
5 | 111221031410300001301 |
6 | 1103250544032514321 |
7 | 34205322536160463 |
oct | 3323775332516711 |
9 | 522274057114414 |
10 | 120121300000201 |
11 | 35302180326765 |
12 | 115803903ab9a1 |
13 | 520450ba4c116 |
14 | 2193c8acd7133 |
15 | dd496d7eb551 |
hex | 6d3feb6a9dc9 |
120121300000201 has 2 divisors, whose sum is σ = 120121300000202. Its totient is φ = 120121300000200.
The previous prime is 120121300000171. The next prime is 120121300000279. The reversal of 120121300000201 is 102000003121021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67077754390201 + 53043545610000 = 8190101^2 + 7283100^2 .
It is a cyclic number.
It is not a de Polignac number, because 120121300000201 - 215 = 120121299967433 is a prime.
It is not a weakly prime, because it can be changed into another prime (120121300000501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060650000100 + 60060650000101.
It is an arithmetic number, because the mean of its divisors is an integer number (60060650000101).
Almost surely, 2120121300000201 is an apocalyptic number.
It is an amenable number.
120121300000201 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121300000201 is an equidigital number, since it uses as much as digits as its factorization.
120121300000201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 120121300000201 its reverse (102000003121021), we get a palindrome (222121303121222).
The spelling of 120121300000201 in words is "one hundred twenty trillion, one hundred twenty-one billion, three hundred million, two hundred one", and thus it is an aban number.
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