Search a number
-
+
1201213330153 is a prime number
BaseRepresentation
bin10001011110101101111…
…001001101001011101001
311020211112121210200001021
4101132231321031023221
5124140041103031103
62315455122252441
7152533120560514
oct21365571151351
94224477720037
101201213330153
11423482677a91
12174977ab7121
1389373a98745
14421d3727d7b
15213a64aabbd
hex117ade4d2e9

1201213330153 has 2 divisors, whose sum is σ = 1201213330154. Its totient is φ = 1201213330152.

The previous prime is 1201213330147. The next prime is 1201213330181. The reversal of 1201213330153 is 3510333121021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 810734566464 + 390478763689 = 900408^2 + 624883^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1201213330153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1201213333153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600606665076 + 600606665077.

It is an arithmetic number, because the mean of its divisors is an integer number (600606665077).

Almost surely, 21201213330153 is an apocalyptic number.

It is an amenable number.

1201213330153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201213330153 is an equidigital number, since it uses as much as digits as its factorization.

1201213330153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 1201213330153 its reverse (3510333121021), we get a palindrome (4711546451174).

The spelling of 1201213330153 in words is "one trillion, two hundred one billion, two hundred thirteen million, three hundred thirty thousand, one hundred fifty-three".