Base | Representation |
---|---|
bin | 10110010111111101… |
… | …11000101001011111 |
3 | 1011000011001200220212 |
4 | 23023332320221133 |
5 | 144100110210044 |
6 | 5303543003035 |
7 | 603446652632 |
oct | 131376705137 |
9 | 34004050825 |
10 | 12012194399 |
11 | 5104630497 |
12 | 23b2a3947b |
13 | 119584414a |
14 | 81d4b3c19 |
15 | 4a487da9e |
hex | 2cbfb8a5f |
12012194399 has 2 divisors, whose sum is σ = 12012194400. Its totient is φ = 12012194398.
The previous prime is 12012194333. The next prime is 12012194417. The reversal of 12012194399 is 99349121021.
It is a strong prime.
It is an emirp because it is prime and its reverse (99349121021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012194399 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012164399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006097199 + 6006097200.
It is an arithmetic number, because the mean of its divisors is an integer number (6006097200).
Almost surely, 212012194399 is an apocalyptic number.
12012194399 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012194399 is an equidigital number, since it uses as much as digits as its factorization.
12012194399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 12012194399 in words is "twelve billion, twelve million, one hundred ninety-four thousand, three hundred ninety-nine".
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