Base | Representation |
---|---|
bin | 10001011110101110010… |
… | …011011101000110110111 |
3 | 11020211120002202020222011 |
4 | 101132232103131012313 |
5 | 124140044333224002 |
6 | 2315455525545051 |
7 | 152533233216616 |
oct | 21365623350667 |
9 | 4224502666864 |
10 | 1201220211127 |
11 | 423486547842 |
12 | 17497a275187 |
13 | 89375337721 |
14 | 421d45d987d |
15 | 213a6db98d7 |
hex | 117ae4dd1b7 |
1201220211127 has 2 divisors, whose sum is σ = 1201220211128. Its totient is φ = 1201220211126.
The previous prime is 1201220211083. The next prime is 1201220211137. The reversal of 1201220211127 is 7211120221021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201220211127 - 223 = 1201211822519 is a prime.
It is a super-2 number, since 2×12012202111272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1201220211098 and 1201220211107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201220211137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600610105563 + 600610105564.
It is an arithmetic number, because the mean of its divisors is an integer number (600610105564).
Almost surely, 21201220211127 is an apocalyptic number.
1201220211127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201220211127 is an equidigital number, since it uses as much as digits as its factorization.
1201220211127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 1201220211127 its reverse (7211120221021), we get a palindrome (8412340432148).
The spelling of 1201220211127 in words is "one trillion, two hundred one billion, two hundred twenty million, two hundred eleven thousand, one hundred twenty-seven".
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