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120122111212093 is a prime number
BaseRepresentation
bin11011010100000000011011…
…110001001011101000111101
3120202022120011110120022222101
4123110000123301023220331
5111221040040432241333
61103251200331545101
734205351616311644
oct3324003361135075
9522276143508871
10120122111212093
1135302557225211
1211580577bbb191
13520460ab29363
142193d2694035b
15dd49b9b3a67d
hex6d401bc4ba3d

120122111212093 has 2 divisors, whose sum is σ = 120122111212094. Its totient is φ = 120122111212092.

The previous prime is 120122111212049. The next prime is 120122111212151. The reversal of 120122111212093 is 390212111221021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73316440500004 + 46805670712089 = 8562502^2 + 6841467^2 .

It is an emirp because it is prime and its reverse (390212111221021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120122111212093 - 29 = 120122111211581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120122111212013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061055606046 + 60061055606047.

It is an arithmetic number, because the mean of its divisors is an integer number (60061055606047).

Almost surely, 2120122111212093 is an apocalyptic number.

It is an amenable number.

120122111212093 is a deficient number, since it is larger than the sum of its proper divisors (1).

120122111212093 is an equidigital number, since it uses as much as digits as its factorization.

120122111212093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 28.

The spelling of 120122111212093 in words is "one hundred twenty trillion, one hundred twenty-two billion, one hundred eleven million, two hundred twelve thousand, ninety-three".