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120122212022257 is a prime number
BaseRepresentation
bin11011010100000000100001…
…110001101111011111110001
3120202022120102111021000112011
4123110000201301233133301
5111221040242234203012
61103251214332402521
734205354252220064
oct3324004161573761
9522276374230464
10120122212022257
11353025a911a3a5
12115805a5916441
135204625994843
142193d360a28db
15dd49c39001a7
hex6d4021c6f7f1

120122212022257 has 2 divisors, whose sum is σ = 120122212022258. Its totient is φ = 120122212022256.

The previous prime is 120122212022179. The next prime is 120122212022261. The reversal of 120122212022257 is 752220212221021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118180358624241 + 1941853398016 = 10871079^2 + 1393504^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120122212022257 is a prime.

It is a super-2 number, since 2×1201222120222572 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120122212022557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061106011128 + 60061106011129.

It is an arithmetic number, because the mean of its divisors is an integer number (60061106011129).

Almost surely, 2120122212022257 is an apocalyptic number.

It is an amenable number.

120122212022257 is a deficient number, since it is larger than the sum of its proper divisors (1).

120122212022257 is an equidigital number, since it uses as much as digits as its factorization.

120122212022257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8960, while the sum is 31.

Adding to 120122212022257 its reverse (752220212221021), we get a palindrome (872342424243278).

The spelling of 120122212022257 in words is "one hundred twenty trillion, one hundred twenty-two billion, two hundred twelve million, twenty-two thousand, two hundred fifty-seven".