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120122213123000 = 23531122773583919
BaseRepresentation
bin11011010100000000100001…
…110101111100001110111000
3120202022120102120022221110102
4123110000201311330032320
5111221040243024414000
61103251214412134532
734205354264453204
oct3324004165741670
9522276376287412
10120122213123000
11353025a9801400
12115805a6167448
135204625c8b87a
142193d362abb04
15dd49c3a6b3d5
hex6d4021d7c3b8

120122213123000 has 192 divisors, whose sum is σ = 310077747907200. Its totient is φ = 43523100192000.

The previous prime is 120122213122973. The next prime is 120122213123027. The reversal of 120122213123000 is 321312221021.

It is an interprime number because it is at equal distance from previous prime (120122213122973) and next prime (120122213123027).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 31725041 + ... + 35308959.

It is an arithmetic number, because the mean of its divisors is an integer number (1614988270350).

Almost surely, 2120122213123000 is an apocalyptic number.

120122213123000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120122213123000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (155038873953600).

120122213123000 is an abundant number, since it is smaller than the sum of its proper divisors (189955534784200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120122213123000 is a wasteful number, since it uses less digits than its factorization.

120122213123000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3584239 (or 3584214 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 120122213123000 its reverse (321312221021), we get a palindrome (120443525344021).

The spelling of 120122213123000 in words is "one hundred twenty trillion, one hundred twenty-two billion, two hundred thirteen million, one hundred twenty-three thousand".