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12012232033132 = 2211232674138921
BaseRepresentation
bin1010111011001101000011…
…0100101100001101101100
31120112100200002210202202121
42232303100310230031230
53033302022400030012
641314202045002324
72346566210410462
oct256632064541554
946470602722677
1012012232033132
1139113a49083a1
1214200742533a4
13691996945c06
142d757635a832
1515c6ebc26a07
hexaecd0d2c36c

12012232033132 has 12 divisors (see below), whose sum is σ = 21040125038296. Its totient is φ = 6000767736480.

The previous prime is 12012232033129. The next prime is 12012232033133. The reversal of 12012232033132 is 23133023221021.

12012232033132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 12012232033097 and 12012232033106.

It is not an unprimeable number, because it can be changed into a prime (12012232033133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1337064969 + ... + 1337073952.

Almost surely, 212012232033132 is an apocalyptic number.

It is an amenable number.

12012232033132 is a deficient number, since it is larger than the sum of its proper divisors (9027893005164).

12012232033132 is a wasteful number, since it uses less digits than its factorization.

12012232033132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2674140048 (or 2674140046 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12012232033132 its reverse (23133023221021), we get a palindrome (35145255254153).

The spelling of 12012232033132 in words is "twelve trillion, twelve billion, two hundred thirty-two million, thirty-three thousand, one hundred thirty-two".

Divisors: 1 2 4 1123 2246 4492 2674138921 5348277842 10696555684 3003058008283 6006116016566 12012232033132