Base | Representation |
---|---|
bin | 10001011110101111000… |
… | …101100010101110010101 |
3 | 11020211121000110100020002 |
4 | 101132233011202232111 |
5 | 124140111213410313 |
6 | 2315501115221045 |
7 | 152533452634244 |
oct | 21365705425625 |
9 | 4224530410202 |
10 | 1201233341333 |
11 | 4234929a5753 |
12 | 174982747785 |
13 | 89377c83c8c |
14 | 421d625695b |
15 | 213a8110058 |
hex | 117af162b95 |
1201233341333 has 2 divisors, whose sum is σ = 1201233341334. Its totient is φ = 1201233341332.
The previous prime is 1201233341309. The next prime is 1201233341359. The reversal of 1201233341333 is 3331433321021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 986491927729 + 214741413604 = 993223^2 + 463402^2 .
It is a cyclic number.
It is not a de Polignac number, because 1201233341333 - 216 = 1201233275797 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201233341296 and 1201233341305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201233341383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600616670666 + 600616670667.
It is an arithmetic number, because the mean of its divisors is an integer number (600616670667).
Almost surely, 21201233341333 is an apocalyptic number.
It is an amenable number.
1201233341333 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201233341333 is an equidigital number, since it uses as much as digits as its factorization.
1201233341333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 1201233341333 its reverse (3331433321021), we get a palindrome (4532666662354).
The spelling of 1201233341333 in words is "one trillion, two hundred one billion, two hundred thirty-three million, three hundred forty-one thousand, three hundred thirty-three".
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