Base | Representation |
---|---|
bin | 11011010100000111110010… |
… | …000011100100010100011011 |
3 | 120202100022112100012111210001 |
4 | 123110013302003210110123 |
5 | 111221202220314321131 |
6 | 1103254543304233431 |
7 | 34206051264202411 |
oct | 3324076203442433 |
9 | 522308470174701 |
10 | 120130001323291 |
11 | 35305935a67573 |
12 | 11581bba46b877 |
13 | 52052976758cb |
14 | 21944747a12b1 |
15 | dd4ccc67b261 |
hex | 6d41f20e451b |
120130001323291 has 2 divisors, whose sum is σ = 120130001323292. Its totient is φ = 120130001323290.
The previous prime is 120130001323159. The next prime is 120130001323303. The reversal of 120130001323291 is 192323100031021.
It is a strong prime.
It is an emirp because it is prime and its reverse (192323100031021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120130001323291 - 213 = 120130001315099 is a prime.
It is a super-2 number, since 2×1201300013232912 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120130001323691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065000661645 + 60065000661646.
It is an arithmetic number, because the mean of its divisors is an integer number (60065000661646).
Almost surely, 2120130001323291 is an apocalyptic number.
120130001323291 is a deficient number, since it is larger than the sum of its proper divisors (1).
120130001323291 is an equidigital number, since it uses as much as digits as its factorization.
120130001323291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 28.
The spelling of 120130001323291 in words is "one hundred twenty trillion, one hundred thirty billion, one million, three hundred twenty-three thousand, two hundred ninety-one".
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