Base | Representation |
---|---|
bin | 11011010100000111110010… |
… | …000011100100010010010111 |
3 | 120202100022112100012111121011 |
4 | 123110013302003210102113 |
5 | 111221202220314320114 |
6 | 1103254543304233051 |
7 | 34206051264202132 |
oct | 3324076203442227 |
9 | 522308470174534 |
10 | 120130001323159 |
11 | 35305935a67463 |
12 | 11581bba46b787 |
13 | 5205297675829 |
14 | 21944747a1219 |
15 | dd4ccc67b1c4 |
hex | 6d41f20e4497 |
120130001323159 has 2 divisors, whose sum is σ = 120130001323160. Its totient is φ = 120130001323158.
The previous prime is 120130001323151. The next prime is 120130001323291. The reversal of 120130001323159 is 951323100031021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120130001323159 - 23 = 120130001323151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 120130001323159.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120130001323151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065000661579 + 60065000661580.
It is an arithmetic number, because the mean of its divisors is an integer number (60065000661580).
Almost surely, 2120130001323159 is an apocalyptic number.
120130001323159 is a deficient number, since it is larger than the sum of its proper divisors (1).
120130001323159 is an equidigital number, since it uses as much as digits as its factorization.
120130001323159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 31.
The spelling of 120130001323159 in words is "one hundred twenty trillion, one hundred thirty billion, one million, three hundred twenty-three thousand, one hundred fifty-nine".
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