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120130011003000 = 233531991129178231
BaseRepresentation
bin11011010100000111110010…
…101000011111100001111000
3120202100022120000102021211210
4123110013302220133201320
5111221202230304044000
61103254544251523120
734206051442366215
oct3324076250374170
9522308500367753
10120130011003000
1135305940479029
12115820017594a0
13520529968474b
142194475ba0b0c
15dd4ccd43e350
hex6d41f2a1f878

120130011003000 has 256 divisors, whose sum is σ = 377024843520000. Its totient is φ = 31845280896000.

The previous prime is 120130011002971. The next prime is 120130011003043. The reversal of 120130011003000 is 300110031021.

120130011003000 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 673923885 + ... + 674102115.

It is an arithmetic number, because the mean of its divisors is an integer number (1472753295000).

Almost surely, 2120130011003000 is an apocalyptic number.

120130011003000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120130011003000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (188512421760000).

120130011003000 is an abundant number, since it is smaller than the sum of its proper divisors (256894832517000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120130011003000 is a wasteful number, since it uses less digits than its factorization.

120130011003000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 179583 (or 179569 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 120130011003000 its reverse (300110031021), we get a palindrome (120430121034021).

The spelling of 120130011003000 in words is "one hundred twenty trillion, one hundred thirty billion, eleven million, three thousand".