Base | Representation |
---|---|
bin | 11011010100000111111110… |
… | …101011100000100001101111 |
3 | 120202100100002002201220101201 |
4 | 123110013332223200201233 |
5 | 111221203134024320421 |
6 | 1103255020311550331 |
7 | 34206056445352015 |
oct | 3324077653404157 |
9 | 522310062656351 |
10 | 120130213120111 |
11 | 35305a34577667 |
12 | 1158205938b3a7 |
13 | 52052cc50057c |
14 | 21944949748b5 |
15 | dd4ce1065b91 |
hex | 6d41feae086f |
120130213120111 has 2 divisors, whose sum is σ = 120130213120112. Its totient is φ = 120130213120110.
The previous prime is 120130213120069. The next prime is 120130213120133. The reversal of 120130213120111 is 111021312031021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120130213120111 - 219 = 120130212595823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120130213123111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065106560055 + 60065106560056.
It is an arithmetic number, because the mean of its divisors is an integer number (60065106560056).
Almost surely, 2120130213120111 is an apocalyptic number.
120130213120111 is a deficient number, since it is larger than the sum of its proper divisors (1).
120130213120111 is an equidigital number, since it uses as much as digits as its factorization.
120130213120111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 120130213120111 its reverse (111021312031021), we get a palindrome (231151525151132).
The spelling of 120130213120111 in words is "one hundred twenty trillion, one hundred thirty billion, two hundred thirteen million, one hundred twenty thousand, one hundred eleven".
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