Base | Representation |
---|---|
bin | 10110011000000100… |
… | …00101101101011111 |
3 | 1011000012122101002121 |
4 | 23030002011231133 |
5 | 144100314044320 |
6 | 5304013003411 |
7 | 603460051501 |
oct | 131402055537 |
9 | 34005571077 |
10 | 12013034335 |
11 | 5105054555 |
12 | 23b3183567 |
13 | 1195a79553 |
14 | 81d651d71 |
15 | 4a49978aa |
hex | 2cc085b5f |
12013034335 has 32 divisors (see below), whose sum is σ = 15289021440. Its totient is φ = 9036116352.
The previous prime is 12013034321. The next prime is 12013034381. The reversal of 12013034335 is 53343031021.
12013034335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12013034335 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8077962 + ... + 8079448.
It is an arithmetic number, because the mean of its divisors is an integer number (477781920).
Almost surely, 212013034335 is an apocalyptic number.
12013034335 is a deficient number, since it is larger than the sum of its proper divisors (3275987105).
12013034335 is a wasteful number, since it uses less digits than its factorization.
12013034335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2095.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 12013034335 its reverse (53343031021), we get a palindrome (65356065356).
The spelling of 12013034335 in words is "twelve billion, thirteen million, thirty-four thousand, three hundred thirty-five".
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