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120130423 = 722974941
BaseRepresentation
bin1110010100100…
…00101101110111
322101001020221221
413022100231313
5221223133143
615530451211
72656043320
oct712205567
9271036857
10120130423
11618a0846
1234293b07
131bb713ba
1411d51447
15a82e2ed
hex7290b77

120130423 has 8 divisors (see below), whose sum is σ = 137893280. Its totient is φ = 102517920.

The previous prime is 120130393. The next prime is 120130427. The reversal of 120130423 is 324031021.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120130423 - 25 = 120130391 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120130397 and 120130406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120130427) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35868 + ... + 39073.

It is an arithmetic number, because the mean of its divisors is an integer number (17236660).

Almost surely, 2120130423 is an apocalyptic number.

120130423 is a deficient number, since it is larger than the sum of its proper divisors (17762857).

120130423 is an equidigital number, since it uses as much as digits as its factorization.

120130423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75177.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 120130423 is about 10960.4025017332. The cubic root of 120130423 is about 493.4210450428.

Adding to 120130423 its reverse (324031021), we get a palindrome (444161444).

The spelling of 120130423 in words is "one hundred twenty million, one hundred thirty thousand, four hundred twenty-three".

Divisors: 1 7 229 1603 74941 524587 17161489 120130423