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120130427 is a prime number
BaseRepresentation
bin1110010100100…
…00101101111011
322101001020222002
413022100231323
5221223133202
615530451215
72656043324
oct712205573
9271036862
10120130427
11618a084a
1234293b0b
131bb713c1
1411d5144b
15a82e302
hex7290b7b

120130427 has 2 divisors, whose sum is σ = 120130428. Its totient is φ = 120130426.

The previous prime is 120130393. The next prime is 120130429. The reversal of 120130427 is 724031021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120130427 is a prime.

Together with 120130429, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 120130399 and 120130408.

It is not a weakly prime, because it can be changed into another prime (120130429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065213 + 60065214.

It is an arithmetic number, because the mean of its divisors is an integer number (60065214).

Almost surely, 2120130427 is an apocalyptic number.

120130427 is a deficient number, since it is larger than the sum of its proper divisors (1).

120130427 is an equidigital number, since it uses as much as digits as its factorization.

120130427 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 20.

The square root of 120130427 is about 10960.4026842083. The cubic root of 120130427 is about 493.4210505193.

Adding to 120130427 its reverse (724031021), we get a palindrome (844161448).

The spelling of 120130427 in words is "one hundred twenty million, one hundred thirty thousand, four hundred twenty-seven".