Base | Representation |
---|---|
bin | 1010111011010000001011… |
… | …1100000001011111111111 |
3 | 1120112102211200212222012112 |
4 | 2232310002330001133333 |
5 | 3033310233120104002 |
6 | 41314421321524235 |
7 | 2346626100063035 |
oct | 256640274013777 |
9 | 46472750788175 |
10 | 12013072816127 |
11 | 3911796474079 |
12 | 142026994367b |
13 | 691a9bba7b46 |
14 | 2d7615ca0555 |
15 | 15c74a957852 |
hex | aed02f017ff |
12013072816127 has 2 divisors, whose sum is σ = 12013072816128. Its totient is φ = 12013072816126.
The previous prime is 12013072816093. The next prime is 12013072816207. The reversal of 12013072816127 is 72161827031021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12013072816127 - 214 = 12013072799743 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013072876127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006536408063 + 6006536408064.
It is an arithmetic number, because the mean of its divisors is an integer number (6006536408064).
Almost surely, 212013072816127 is an apocalyptic number.
12013072816127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013072816127 is an equidigital number, since it uses as much as digits as its factorization.
12013072816127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56448, while the sum is 41.
Adding to 12013072816127 its reverse (72161827031021), we get a palindrome (84174899847148).
The spelling of 12013072816127 in words is "twelve trillion, thirteen billion, seventy-two million, eight hundred sixteen thousand, one hundred twenty-seven".
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