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120131022041404 = 22112730250500941
BaseRepresentation
bin11011010100001000101110…
…111001010011000100111100
3120202100102011110212100210121
4123110020232321103010330
5111221211313120311104
61103255232445544324
734206115500153103
oct3324105671230474
9522312143770717
10120131022041404
113530630a151160
12115822442750a4
1352053cac8801a
14219453018303a
15dd4d3c0a1254
hex6d422ee5313c

120131022041404 has 12 divisors (see below), whose sum is σ = 229341042079128. Its totient is φ = 54605010018800.

The previous prime is 120131022041351. The next prime is 120131022041413. The reversal of 120131022041404 is 404140220131021.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1365125250427 + ... + 1365125250514.

It is an arithmetic number, because the mean of its divisors is an integer number (19111753506594).

Almost surely, 2120131022041404 is an apocalyptic number.

It is an amenable number.

120131022041404 is a deficient number, since it is larger than the sum of its proper divisors (109210020037724).

120131022041404 is a wasteful number, since it uses less digits than its factorization.

120131022041404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2730250500956 (or 2730250500954 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 120131022041404 its reverse (404140220131021), we get a palindrome (524271242172425).

The spelling of 120131022041404 in words is "one hundred twenty trillion, one hundred thirty-one billion, twenty-two million, forty-one thousand, four hundred four".

Divisors: 1 2 4 11 22 44 2730250500941 5460501001882 10921002003764 30032755510351 60065511020702 120131022041404