Base | Representation |
---|---|
bin | 11011010100001000101110… |
… | …111001100001100000100111 |
3 | 120202100102011110222100220001 |
4 | 123110020232321201200213 |
5 | 111221211313124204034 |
6 | 1103255232451122131 |
7 | 34206115500520333 |
oct | 3324105671414047 |
9 | 522312143870801 |
10 | 120131022100519 |
11 | 3530630a191611 |
12 | 115822442a3347 |
13 | 52053caca8bc1 |
14 | 219453019a7c3 |
15 | dd4d3c0b3a14 |
hex | 6d422ee61827 |
120131022100519 has 2 divisors, whose sum is σ = 120131022100520. Its totient is φ = 120131022100518.
The previous prime is 120131022100429. The next prime is 120131022100543. The reversal of 120131022100519 is 915001220131021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120131022100519 - 27 = 120131022100391 is a prime.
It is a super-4 number, since 4×1201310221005194 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120131022100819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065511050259 + 60065511050260.
It is an arithmetic number, because the mean of its divisors is an integer number (60065511050260).
Almost surely, 2120131022100519 is an apocalyptic number.
120131022100519 is a deficient number, since it is larger than the sum of its proper divisors (1).
120131022100519 is an equidigital number, since it uses as much as digits as its factorization.
120131022100519 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 28.
The spelling of 120131022100519 in words is "one hundred twenty trillion, one hundred thirty-one billion, twenty-two million, one hundred thousand, five hundred nineteen".
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