Base | Representation |
---|---|
bin | 10001011110110011101… |
… | …010110100001101000010 |
3 | 11020211210101010020110200 |
4 | 101132303222310031002 |
5 | 124140240404033442 |
6 | 2315512503110030 |
7 | 152535405253464 |
oct | 21366352641502 |
9 | 4224711106420 |
10 | 1201310221122 |
11 | 423522335670 |
12 | 1749a4442316 |
13 | 8938ab9108b |
14 | 4220254a134 |
15 | 213aec4934c |
hex | 117b3ab4342 |
1201310221122 has 48 divisors (see below), whose sum is σ = 2839739217120. Its totient is φ = 363997670400.
The previous prime is 1201310221037. The next prime is 1201310221123. The reversal of 1201310221122 is 2211220131021.
1201310221122 is a `hidden beast` number, since 12 + 0 + 1 + 310 + 221 + 122 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 1201310221095 and 1201310221104.
It is not an unprimeable number, because it can be changed into a prime (1201310221123) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1760497 + ... + 2345627.
It is an arithmetic number, because the mean of its divisors is an integer number (59161233690).
Almost surely, 21201310221122 is an apocalyptic number.
1201310221122 is an abundant number, since it is smaller than the sum of its proper divisors (1638428995998).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201310221122 is a wasteful number, since it uses less digits than its factorization.
1201310221122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 595519 (or 595516 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 1201310221122 its reverse (2211220131021), we get a palindrome (3412530352143).
The spelling of 1201310221122 in words is "one trillion, two hundred one billion, three hundred ten million, two hundred twenty-one thousand, one hundred twenty-two".
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